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1=1t-5t^2
We move all terms to the left:
1-(1t-5t^2)=0
We get rid of parentheses
5t^2-1t+1=0
a = 5; b = -1; c = +1;
Δ = b2-4ac
Δ = -12-4·5·1
Δ = -19
Delta is less than zero, so there is no solution for the equation
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